Beginner Exercism • javascript

Perfect Numbers

Challenge Overview

Determine if a number is perfect, abundant, or deficient based on Nicomachus' (60 - 120 CE) classification scheme for positive integers.

Source: Exercism javascript/perfect-numbers

💡 View Solution

export const classify = (n) => {
  if (n <= 0) throw new Error('Classification is only possible for positive integers.');
  let sum = 0;
  for (let i = 1; i < n; i++) if (n % i === 0) sum += i;
  if (sum === n) return 'perfect';
  if (sum > n) return 'abundant';
  return 'deficient';
};